Answer (1 of 2) Ordinary Differential Equation x^2\,y'' xy' 2y = 0 \tag*{} has solution y_1 = x\,\sin(\ln x) \tag*{} To find a second solution we can use Reduction of order First we rewrite differential equation into the form y'' p(x)y' q(x)y = 0 \tag*{} by dividing through byPrecalculus Geometry of an Ellipse Standard Form of the Equation 1 Answer2xy'=(y to the power of 2x to the power of 2) to the power of 1/22y;
Assignment 1
